√完了しました！ y=-x^2 graph 259128-Y x - 2 graphed
Y X 3
Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledgeHow do you graph y=x2Video instruction on how to graph the equation y=x2
Y x - 2 graphed
Y x - 2 graphed-Divide 1, the coefficient of the x term, by 2 to get \frac{1}{2} Then add the square of \frac{1}{2} to both sides of the equation This step makes the left hand side of the equation a perfect squareSwap sides so that all variable terms are on the left hand side x^ {2}2x=y4 Subtract 4 from both sides x^ {2}2x1^ {2}=y41^ {2} Divide 2, the coefficient of the x term, by 2 to get 1 Then add the square of 1 to both sides of the equation This step makes the left hand side of
Draw The Graph Of Y X 2 And Y X 2 And Hence Solve The Equation X 2 X 2 0
As an alternative to what @pasmith wrote, I would sketch (by hand) a graph of y = x/(x 2), noting that there is an obvious vertical asymptote around x = 2 Also, because this function is the quotient of two polynomials of the same degree, there will be a horizontal asymptote Once you have figured out what the graph looks like around the vertical asymptote and for large or veryAnswer (1 of 15) x^2y^2=0 x^2=y^2 x=\sqrt{y^2} x=\sqrt{y^2} This is the equation of a straight line x=y and x=y Or the equivalent form y=x and y=x graph{y=x2 10, 10, 5, 5} Follow the rule of y=mxc mx is the gradient c is the y intercept c = 2 so that is where the line crosses on the y axis the gradient is 1 as there is no number in front of the x so you would go across one and then up one and mark the point
Answer (1 of 9) You have 4 of the necessary critical points The y intercept (2) (3) (1) = 6 and the three x itercepts 2, 3 and 1 To find the turning points, find where the derivative is zero y = x^3–4x^2x6 \frac{dy}{dx} = 3x^2 8x 1 = 0 \implies x = \frac{4 \pm \sqrt{13}}{3} = 2Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledgeThe quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}xy6=0 x 2 x − y − 6 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 1 for b, and 6y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a}
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For example, consider the functions g (x) = x 2 − 3 and h (x) = x 2 3 Begin by evaluating for some values of the independent variable x Now plot the points and compare the graphs of the functions g and h to the basic graph of f ( x ) = x 2 , which is shown using a dashed grey curve belowAnswer The graphs of y = x2 and y = x2 intersect at the x coordinates of −1 and 2 Hence the roots of the quadratic equation x2 −x−2= 0 are {−1,2}
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